"how to print a single-precision float with printf" Code Answer
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%fformat specifier wants a
double. there is no way to get printf to accept a
c's default argument promotions specify that calls to variadic functions like
foo(char *fmt, ...)promote
double, and perform the usual integer promotions of narrow integer types to
int, for trailing args that match the
...part of the prototype. (the same applies to all args for calling functions with no prototype.) n1570 126.96.36.199 function calls, subsections 6 and 7.
thus c provides no way for a caller to pass a
printf, so it has no conversion for it, and
%lfalso works for
double, assuming the implementation ignores it for non-integer /
doubleis required in c99/c11 and c++11
printfimplementations, so you can safely use the same
%lfformat string with a
scanfis different, because
double *aren't affected by those promotions.
in this case, load with
cvtss2sd .num(%rip), %xmm0.
if you look at compiler output, you'll see gcc do everything you did, and
pxor-zero the register first to break the false dependency on the old value of
cvtss2sd's poor design leaves the upper 64 bits of the destination unchanged.) gcc errs on the side of caution, and inserts xor-zeroing instructions to break false dependencies in many cases.
you're probably getting 0 because the upper bits of xmm0 happen to be zero. when
printflooks at the low 64 bits of xmm0 as a
double(ieee binary64 on x86), it finds the bit pattern for
123.4fin the low 32 bits of the mantissa, and the rest zero. as a 64-bit
double, this bit-pattern represents a very small (subnormal) number, so it comes out as zero with
you can try the equivalent with a
float, (e.g. on http://www.h-schmidt.net/floatconverter/ieee754.html), setting some bits in the low half to see what you get.
if you used
%g(scientific notation) or
%a(hex representation of the
doublebit-pattern), the non-zero bits would show up. (unless you had denormals are zero mode enabled in the mxcsr.)