"how to print a single-precision float with printf" Code Answer
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printf(3)
's%f
format specifier wants adouble
. there is no way to get printf to accept afloat
, onlydouble
orlong double
.c's default argument promotions specify that calls to variadic functions like
foo(char *fmt, ...)
promotefloat
todouble
, and perform the usual integer promotions of narrow integer types toint
, for trailing args that match the...
part of the prototype. (the same applies to all args for calling functions with no prototype.) n1570 6.5.2.2 function calls, subsections 6 and 7.thus c provides no way for a caller to pass a
float
toprintf
, so it has no conversion for it, and%f
meansdouble
. (%lf
also works fordouble
, assuming the implementation ignores it for non-integer /wchar_t
conversions. accepting%lf
fordouble
is required in c99/c11 and c++11printf
implementations, so you can safely use the same%lf
format string with adouble
forprintf
andscanf
).note that
scanf
is different, becausefloat *
anddouble *
aren't affected by those promotions.in this case, load with
cvtss2sd .num(%rip), %xmm0
.if you look at compiler output, you'll see gcc do everything you did, and
pxor
-zero the register first to break the false dependency on the old value of%xmm0
. (cvtss2sd
's poor design leaves the upper 64 bits of the destination unchanged.) gcc errs on the side of caution, and inserts xor-zeroing instructions to break false dependencies in many cases.you're probably getting 0 because the upper bits of xmm0 happen to be zero. when
printf
looks at the low 64 bits of xmm0 as adouble
(ieee binary64 on x86), it finds the bit pattern for123.4f
in the low 32 bits of the mantissa, and the rest zero. as a 64-bitdouble
, this bit-pattern represents a very small (subnormal) number, so it comes out as zero with%f
.you can try the equivalent with a
float
, (e.g. on http://www.h-schmidt.net/floatconverter/ieee754.html), setting some bits in the low half to see what you get.if you used
%g
(scientific notation) or%a
(hex representation of thedouble
bit-pattern), the non-zero bits would show up. (unless you had denormals are zero mode enabled in the mxcsr.)