"is the != check thread safe?" Code Answer
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in the absence of synchronization this code
may produce
true. this is the bytecode fortest()as we can see it loads field
ato local vars twice, it's a non-atomic operation, ifawas changed in between by another thread comparison may producefalse.also, memory visibility problem is relevant here, there is no guarantee that changes to
amade by another thread will be visible to the current thread.