"c++ base constructor calling with parameter that will be constructed in the derived constructor" Code Answer
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first, the solution: use a static member function or a nonmember function.
as for the behavior,
derived::generatename()
will be called. the long sentence in the c++ standard that defines this behavior says (c++03 12.7/3):because the constructor being executed at the time of the virtual call is the
derived
constructor,derived::generatename()
is called.a now-deleted answer rightly referred to an article by scott meyers that recommends "never call virtual functions during construction or destruction." the rules for what overrider gets called are complex and difficult to remember.