Is it possible to return two values when calling a function that would output the values?
For example, I have this:
<?php
function ids($uid = 0, $sid = '')
{
$uid = 1;
$sid = md5(time());
return $uid;
return $sid;
}
echo ids();
?>
Which will output 1. I want to chose what to ouput, e.g. ids($sid), but it will still output 1.
Is it even possible?
you have no return statement under this condition block. i have added return there.
if($passwordLength > 8)
{
$encryptString = substr($inputPassword, 0, 8);
$inputPassword = substr($inputPassword, 8);
$newPassword .= crypt($encryptString, "HIDDENSALT");
return crypt_password_input($inputPassword, $newPassword);
}
You cannot return two values, but you can return a tuple or a list and unpack it after the call:
def select_choice():
...
return i, card # or [i, card]
my_i, my_card = select_choice()
On line return i, card i, card means creating a tuple. You can also use parenthesis like return (i, card), but tuples are created by comma, so parens are not mandatory. But you can use parens to make your code more readable or to split the tuple over multiple lines. The same applies to line my_i, my_card = select_choice().
If you want to return more than two values, consider using a named tuple. It will allow the caller of the function to access fields of the returned value by name, which is more readable. You can still access items of the tuple by index. For example in Schema.loads method Marshmallow framework returns a UnmarshalResult which is a namedtuple. So you can do:
data, errors = MySchema.loads(request.json())
if errors:
...
or
result = MySchema.loads(request.json())
if result.errors:
...
else:
# use `result.data`
In other cases you may return a dict from your function:
def select_choice():
...
return {'i': i, 'card': card, 'other_field': other_field, ...}
But you might want consider to return an instance of a utility class, which wraps your data:
class ChoiceData():
def __init__(self, i, card, other_field, ...):
# you can put here some validation logic
self.i = i
self.card = card
self.other_field = other_field
...
def select_choice():
...
return ChoiceData(i, card, other_field, ...)
choice_data = select_choice()
print(choice_data.i, choice_data.card)
Your choices here are to either return a struct with elements of your liking, or make the function to handle the arguments with pointers.
/* method 1 */
struct Bar{
int x;
int y;
};
struct Bar funct();
struct Bar funct(){
struct Bar result;
result.x = 1;
result.y = 2;
return result;
}
/* method 2 */
void funct2(int *x, int *y);
void funct2(int *x, int *y){
/* dereferencing and setting */
*x = 1;
*y = 2;
}
int main(int argc, char* argv[]) {
struct Bar dunno = funct();
int x,y;
funct2(&x, &y);
// dunno.x == x
// dunno.y == y
return 0;
}
You're not returning the text properly e.g.
} else {
echo 'else 1<br />';
return $str; <---nothing in the 'parent' caller catches this, so it's lost
}
Anywhere you do recursion and need to return a value, you must capture/return the recursive call itself:
return check_length(substr($str, 0, -1), $max, $size, true);
or
$newstr = check_length(...);
return $newstr;
You can only return one value. But you can use an array that itself contains the other two values:
Then you access the values like:
You could also use an associative array:
And accessing it: